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CS610 Computer Networks Assignment 3 Solution Fall 2012

Question 1                                                                                                                                      [10 Marks] Write the correct answer of given parameter against each of following networking devices.

Note: You are not required to give detail against each parameter corresponding to given devices. Just mention the appropriate number(s) / names required against each given device.
 

 Parameters

 

Router

 

 

Switch

 

 

Hub

 

 

Bridge

 

No. of broadcast domain(s)

No. of collision domain(s)

Layer(s )on which device work

Data travelling format

 

Address used on Device

Solution:

 Question 2                                                                                                                                      [5 Marks]

 

Write the subnet bits / borrowed bits, default mask and subnet mask against each of following IP address.


 

164.2.34.10/27

101.2.3.18/16

210.222.5.121/29

150.1.25.20/18

10.2.7.20/28

Subnet bits

Default mask

Subnet mask

 

Question 1                                                                                                                                     

Write the correct answer of given parameter against each of following networking devices.

Solution:

 

Parameters

 

 

Router

 

 

Switch

 

 

Hub

 

 

Bridge

 

No. of broadcast domain(s)

No collision.

(No Vlans)1 broadcast domain

Single broadcast doamin

1

No. of collision domain(s)

One collision

1 per port

Single collision domain

1

Layer(s )on which device work

Layer 3 of OSI Model(Network Layer)

Layer 2 of the OSI Model (data link)

Layer 1 (Physical Layer of the OSI Model)

Layer 2 (Data Link)

Data travelling format

Data travel in packets

Frame Format

Bit Format

Frame Format

Address used on Device

IP address are used

MAC address are used

/

Mac Address are used

 

Question 2                                                                                                                                     

 

Write the subnet bits / borrowed bits, default mask and subnet mask against each of following IP address.

Solution:



 

 

 

164.2.34.10/27

 

101.2.3.18/16

210.222.5.121/29

150.1.25.20/18

10.2.7.20/28

Subnet bits

 

5

16

3

14

4

Default mask

 

255.255.0.0

 

 

255.0.0.0

 

255.255.255.0

 

255.255.0.0

 

255.0.0.0

Subnet mask

 

 

255.255.255.224

 



255.255.0.0

 



255.255.255.248

 



255.255.192.0


255.255.255.240

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