CS610 VU Assignment No 4 Spring 2012 Solution

1. How many subnets and hosts per subnet can you get from the network 174.20.0.0/23 Remember for host part at least 2 bits are required? [10 Marks]

The number of hosts from /23 it means that 23 bits are on while others
are off. So take number of bits which are off. For there are 9 bits, which are
off.
2^9 -2 =510 Number of hosts for number of subnets.
Since it class B its default is /16 but according to the question is /23.
So
23-16=7
Hence to get subnets =2^7 =128
Q.2. Write the class name against each IP address given below,

 

IP Address

Class

122.25.125.10  A
191.228.30.20  B
224.25.239.55/8 D
192.168.88.100/24  C
222.127.160.79/19  C

 

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